gtq4 发布的帖子

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import sensor, image, time
from pyb import UART
sensor.reset() # Reset and initialize the sensor.
sensor.set_pixformat(sensor.RGB565) # Set pixel format to RGB565 (or GRAYSCALE)
sensor.set_framesize(sensor.QVGA) # Set frame size to QVGA (320x240)
sensor.skip_frames(time = 2000) # Wait for settings take effect.
clock = time.clock()
uart=UART(3,9600)# Create a clock object to track the FPS.
uart.init(9600,bits=8,parity=None,stop=1)
list=[1,1,2]
while(True):

clock.tick() 
uart.write(list)

我现在这样写他会出现 需要具有缓冲协议的对象，该怎么改。

# 多颜色组合识别
。

import sensor, image, time
sensor.reset()
sensor.set_pixformat(sensor.RGB565)
sensor.set_framesize(sensor.QVGA)
sensor.skip_frames(time = 2000)
sensor.set_auto_gain(False) # must be turned off for color tracking
sensor.set_auto_whitebal(False) # must be turned off for color tracking
clock = time.clock(）


while(True):
    clock.tick()
    img = sensor.snapshot()
    for blob in img.find_blobs(thresholds, pixels_threshold=100, area_threshold=100, merge=True):
        if blob.code() == 3: # r/g code
            img.draw_rectangle(blob.rect())
            img.draw_cross(blob.cx(), blob.cy())
            img.draw_string(blob.x() + 2, blob.y() + 2, "r/g")
        if blob.code() == 5: # r/b code
            img.draw_rectangle(blob.rect())
            img.draw_cross(blob.cx(), blob.cy())
            img.draw_string(blob.x() + 2, blob.y() + 2, "r/b")
        if blob.code() == 6: # g/b code
            img.draw_rectangle(blob.rect())
            img.draw_cross(blob.cx(), blob.cy())
            img.draw_string(blob.x() + 2, blob.y() + 2, "g/b")
        if blob.code() == 7: # r/g/b code
            img.draw_rectangle(blob.rect())
            img.draw_cross(blob.cx(), blob.cy())
            img.draw_string(blob.x() + 2, blob.y() + 2, "r/g/b")
    print(clock.fps())

blob.code=？ 这个数字是因为红色色块是1，绿色是2，蓝色是4吗，怎么得来的。如果我只想判断是否是红色色块是不是就是 blob.code=1，绿色就是 blob.code=2

求程序的逻辑和思路，如色块顺序是321，识别后将321打包发送给串口

openmv有相应代码可以实现吗

那我通过摄像头识别三个大小一样的色块，知道他们的位置后，将他们所处的位置发给单片机也不能实现吗

前提是色块大小一，就识别离摄像头最近的

如摄像头拍了一张图片，图片中有三种颜色的色块。我想识别离摄像头最近的色块，该怎么写

您好，我的意思是假如识别二维码，二维码内容会在串行终端显示，我想将其内容显示屏幕上

具体用到那些代码，需要哪些环节

那是不是 a="code.payload"
while True:
for code in img.find_qrcodes()
a=code.payload()
img.draw()
lcd.display(img)

请问下第一行要显示的字符串=“”怎么用代码表示

import sensor, image, time, lcd, pyb

sensor.reset()
sensor.set_pixformat(sensor.RGB565)
sensor.set_framesize(sensor.QVGA)
sensor.skip_frames(time = 2000)
sensor.set_auto_gain(False) # must turn this off to prevent image washout...
clock = time.clock()
lcd.init() # Initialize the lcd screen.

while(True):
    clock.tick()
    img = sensor.snapshot()


    for i in range(10):
        x = (pyb.rng() % (2*img.width())) - (img.width()//2)
        y = (pyb.rng() % (2*img.height())) - (img.height()//2)
        r = (pyb.rng() % 127) + 128
        g = (pyb.rng() % 127) + 128
        b = (pyb.rng() % 127) + 128


    img.lens_corr(1.8) # strength of 1.8 is good for the 2.8mm lens.
    for code in img.find_qrcodes():
        img.draw_rectangle(code.rect(), color = (255, 0, 0))
        print(code)
        img.draw_string(x, y, code.payload(), color = (255, 0, 0), scale = 5, mono_space = False)

    lcd.display(img)
    print(clock.fps())

我看到了，哇没注意

检查了好几遍，自己也改了，不对，一扫到二维码就出现错误。。。。

# QRCode Example
#
# This example shows the power of the OpenMV Cam to detect QR Codes
# using lens correction (see the qrcodes_with_lens_corr.py script for higher performance).

import sensor, image, time, lcd, pyb

sensor.reset()
sensor.set_pixformat(sensor.RGB565)
sensor.set_framesize(sensor.QVGA)
sensor.skip_frames(time = 2000)
sensor.set_auto_gain(False) # must turn this off to prevent image washout...
clock = time.clock()
lcd.init() # Initialize the lcd screen.

while(True):
    clock.tick()
    img = sensor.snapshot()
    

    for i in range(10):
        x = (pyb.rng() % (2*img.width())) - (img.width()//2)
        y = (pyb.rng() % (2*img.height())) - (img.height()//2)
        r = (pyb.rng() % 127) + 128
        g = (pyb.rng() % 127) + 128
        b = (pyb.rng() % 127) + 128
    

    img.lens_corr(1.8) # strength of 1.8 is good for the 2.8mm lens.
    for code in img.find_qrcodes():
        img.draw_rectangle(code.rect(), color = (255, 0, 0))
        print(code)
        img.draw_string(img.draw_string(x, y, code.payload(), color = (r, g, b), scale = 2, mono_space = False)
)
    lcd.display(img)
    print(clock.fps())

# QRCode Example
#
# This example shows the power of the OpenMV Cam to detect QR Codes
# using lens correction (see the qrcodes_with_lens_corr.py script for higher performance).

import sensor, image, time,lcd

sensor.reset()
sensor.set_pixformat(sensor.RGB565)
sensor.set_framesize(sensor.QVGA)
sensor.skip_frames(time = 2000)
sensor.set_auto_gain(False) # must turn this off to prevent image washout...
clock = time.clock()
lcd.init() # Initialize the lcd screen.

while(True):
    clock.tick()
    img = sensor.snapshot()
    img.lens_corr(1.8) # strength of 1.8 is good for the 2.8mm lens.
    for code in img.find_qrcodes():
        img.draw_rectangle(code.rect(), color = (255, 0, 0))
        print(code)
        img.draw_string(code.payload())
    lcd.display(img)
    print(clock.fps())

还是回复没有足够的位置参数，怎么搞呢，谢谢