经过霍夫变换的直线所得的角度为什么不能直接用数字去减

[1qx5]

zj = 90
pj = 180
if jdc > zj:

jdc = pj - jdc

[1qx5]

@1qx5 为什么if判断不能用

[1qx5]

为什么用if会报错呢

[kidswong999]

如果涉及代码，需要报错提示与全部代码文本，请注意不要贴代码图片

[1qx5]

@kidswong999 错误提示是无效语法

[kidswong999]

请提供全部代码，可以复现错误的代码。

[1qx5]

@kidswong999

enable_lens_corr = False # turn on for straighter lines...

import sensor, image, time

sensor.reset()
sensor.set_pixformat(sensor.RGB565) # grayscale is faster
sensor.set_framesize(sensor.QQVGA)
sensor.skip_frames(time = 2000)
clock = time.clock()

min_degree = 0
max_degree = 179

while(True):
    clock.tick()
    img = sensor.snapshot()
    if enable_lens_corr: img.lens_corr(1.8) # for 2.8mm lens...

    for l in img.find_lines(threshold = 1000, theta_margin = 30, rho_margin = 30):
        if (min_degree <= l.theta()) and (l.theta() <= max_degree):
            img.draw_line(l.line(), color = (255, 0, 0))
            print(l)
  
    jdc =0
    jdc1 =0
    jdc2 =0
    lines = img.find_lines()
    if len(lines) == 3:
       jd1 = lines[0].theta()
       jd2 = lines[1].theta()
       jd3 = lines[2].theta()
       
       jdc = jd1 - jd2 
       jdc1 = jd3 - jd2
       jdc2 = jd1 - jd3

    print(jdc)
    print(jdc1)
    print(jdc2)
    
    zj = 90
    pj = 180
    if jdc > zj:
 
    jdc = 180 - jdc   
    
    print(jdc)
    
    print("FPS %f" % clock.fps())

[kidswong999]

if下一行没有缩进。

[1qx5]

@kidswong999 。。。感谢