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  • 我想问问,我通过识别出圆形再识别颜色,来识别围棋棋子,为什么识别情况很不稳定



    • import sensor, image, time
      import math
      from mywuzi import chess
      from movement import move
      from movement import cgj
      from pyb import UART
      
      
      uart=UART(1,9600)
      sensor.reset()
      sensor.set_pixformat(sensor.RGB565)
      sensor.set_framesize(sensor.QQVGA)
      sensor.skip_frames(time = 2000)
      sensor.set_auto_gain(False) # must be turned off for color tracking
      sensor.set_auto_whitebal(False) # must be turned off for color tracking
      clock = time.clock()
      chess1 = [[0,0,0,0,0,0,0,0,0,0],
               [0,0,0,0,0,0,0,0,0,0],
               [0,0,0,0,0,0,0,0,0,0],
               [0,0,0,0,0,0,0,0,0,0],
               [0,0,0,0,0,0,0,0,0,0],
               [0,0,0,0,0,0,0,0,0,0],
               [0,0,0,0,0,0,0,0,0,0],
               [0,0,0,0,0,0,0,0,0,0],
               [0,0,0,0,0,0,0,0,0,0],
               [0,0,0,0,0,0,0,0,0,0]]
      
      while(True):
          clock.tick()
          img = sensor.snapshot().lens_corr(1.8)
          for c in img.find_circles(threshold = 1500, x_margin = 10, y_margin = 10, r_margin = 10,
                  r_min = 0, r_max = 7, r_step = 2):
              area = (c.x()-c.r(), c.y()-c.r(), 2*c.r(), 2*c.r())
              #area为识别到的圆的区域,即圆的外接矩形框
              statistics = img.get_statistics(roi=area)#像素颜色统计
              #(0,20,-20,20,-10,20)是黑色的阈值,所以当区域内的众数(也就是最多的颜色),范围在这个阈值内,就说明是黑棋。
              #l_mode(),a_mode(),b_mode()是L通道,A通道,B通道的众数。
              if c.r() <= 6:
                  if 0<statistics.l_mode()<26 and -28<statistics.a_mode()<22 and -47<statistics.b_mode()<29:#if the circle is black
                      img.draw_circle(c.x(), c.y(), c.r(), color = (255, 0, 0))#识别到的黑棋用红色的圆框出来
                      m1 = (c.x()-32)/12
                      m2 = (c.x()-20)/12
                      m = int(m2)
                      n1 = (106-c.y())/12
                      n2 = (118-c.y())/12
                      n = int(n2)
                      chess1[m][n] = -1
                  else:
                      img.draw_rectangle(area, color = (255, 255, 255))#将白棋用白色的矩形框出来
                      m1 = (c.x()-32)/12
                      m2 = (c.x()-20)/12
                      m = int(m2)
                      n1 = (106-c.y())/12
                      n2 = (118-c.y())/12
                      n = int(n2)
                      chess1[m][n] = 1
      


    • 具体的图片发一下。





    • @kidswong999 不稳定,总是闪烁



    • 你可以把OpenMV固定在棋盘上面,就可以直接找到对应位置的颜色。就不用找圆。