同时识别圆形和矩形为啥通电后不好使啊

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import sensor, image, time

sensor.reset()
sensor.set_pixformat(sensor.RGB565) # grayscale is faster (160x120 max on OpenMV-M7)
sensor.set_framesize(sensor.QQVGA)
sensor.skip_frames(time = 2000)
clock = time.clock()

while(True):
    clock.tick()
    img = sensor.snapshot()

    # 下面的`threshold`应设置为足够高的值，以滤除在图像中检测到的具有
    # 低边缘幅度的噪声矩形。最适用与背景形成鲜明对比的矩形。

    for r in img.find_rects(threshold = 10000):
        img.draw_rectangle(r.rect(), color = (255, 0, 0))
        for p in r.corners(): img.draw_circle(p[0], p[1], 5, color = (0, 255, 0))
        print(r)
    img1 = sensor.snapshot().lens_corr(1.8)
    for c in img1.find_circles(threshold = 3500, x_margin = 10, y_margin = 10, r_margin = 10,
                r_min = 2, r_max = 100, r_step = 2):
            area = (c.x()-c.r(), c.y()-c.r(), 2*c.r(), 2*c.r())
            #area为识别到的圆的区域，即圆的外接矩形框
            statistics = img1.get_statistics(roi=area)#像素颜色统计
            print(statistics)
            #(0,100,0,120,0,120)是红色的阈值，所以当区域内的众数（也就是最多的颜色），范围在这个阈值内，就说明是红色的圆。
            #l_mode()，a_mode()，b_mode()是L通道，A通道，B通道的众数。
            if 0<statistics.l_mode()<100 and 0<statistics.a_mode()<127 and 0<statistics.b_mode()<127:#if the circle is red
                img.draw_rectangle(area, color = (255, 255, 255))#识别到的红色圆形用红色的圆框出来
            elif 30<statistics.l_mode()<100 and -64<statistics.a_mode()<-8 and -32<statistics.b_mode()<32:#if the circle is red
                img.draw_rectangle(area, color = (255, 255, 255))#识别到的红色圆形用红色的圆框出来
            elif 0<statistics.l_mode()<15 and 0<statistics.a_mode()<-40 and -80<statistics.b_mode()<-20:#if the circle is red
                img.draw_rectangle(area, color = (255, 255, 255))#识别到的红色圆形用红色的圆框出来
    print("FPS %f" % clock.fps())

kidswong999

什么叫做不好使？

具体什么错误？你想解决什么问题？

同时识别圆形和矩形为啥通电后不好使 啊

同时识别圆形和矩形为啥通电后不好使啊