刚刚又发现不打印返回值也会一卡一卡的了
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ws3g
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模块化以后,当我想要在主函数里面打印函数的返回值的时候,图片会一卡一卡的,是运算量太大的问题吗?
其中模块的代码
import sensor, image, time,pyb def find_red_blob(count_flag): red_threshold=(1, 53, 4, 127, 127, 10) sensor.reset() sensor.set_pixformat(sensor.RGB565) sensor.set_framesize(sensor.QQVGA) sensor.skip_frames(10) sensor.set_auto_gain(False) sensor.set_auto_whitebal(False) clock = time.clock() count=0 while(True): count+=1 number=0 img = sensor.snapshot().lens_corr(strength = 1.8, zoom = 1.0) red_blob1 = img.find_blobs([red_threshold],roi=(53,0,45,30)) red_blob2 = img.find_blobs([red_threshold],roi=(0,40,45,30)) red_blob3 = img.find_blobs([red_threshold],roi=(53,40,45,30)) red_blob4 = img.find_blobs([red_threshold],roi=(106,40,45,30)) red_blob5 = img.find_blobs([red_threshold],roi=(53,80,45,30)) if red_blob1!=[]: img.draw_rectangle(red_blob1[0][0:4]) img.draw_cross(red_blob1[0][5], red_blob1[0][6]) number+=1 if red_blob2!=[]: img.draw_rectangle(red_blob2[0][0:4]) img.draw_cross(red_blob2[0][5], red_blob2[0][6]) number+=1 if red_blob3!=[]: img.draw_rectangle(red_blob3[0][0:4]) img.draw_cross(red_blob3[0][5], red_blob3[0][6]) number+=1 if red_blob4!=[]: img.draw_rectangle(red_blob4[0][0:4]) img.draw_cross(red_blob4[0][5], red_blob4[0][6]) number+=1 if red_blob5!=[]: img.draw_rectangle(red_blob5[0][0:4]) img.draw_cross(red_blob5[0][5], red_blob5[0][6]) number+=1 #print(number) if count>count_flag: break return number 主函数的代码: import sensor, image, time import black_blob,red_blob while(True): #print(clock.fps()) # Note: OpenMV Cam runs about half as fast when connected red_blob.find_red_blob(1000) #black_blob.find_black_blob(1000,0,0) a=red_blob.find_red_blob(1000) #print(a)