不能通过调pid解决吗

视频的代码和官网的例程代码都试过了，还是没有拐弯效果怎么办，只能直线走

如何用测距板使追小球的小车实现避障功能，写一个测距模块然后调用实现避障吗

@kidswong999 能有什么办法解决吗？

@kidswong999 好的，解决了谢谢

@kidswong999 是下官网最新的ide了

和视频步骤点击运行的时候没有提示保存VL53L1X，然后报错没有这个py文件怎么办

from machine import I2C
from vl53l1x import VL53L1X
import time

i2c = I2C(2)
distance = VL53L1X(i2c)

while True:
    print("range: mm ", distance.read())
    time.sleep_ms(50)

官网追小车实例的代码
car.py

from pyb import Pin, Timer
inverse_left=False #change it to True to inverse left wheel
inverse_right=False #change it to True to inverse right wheel

ain1 = Pin('P0', Pin.OUT_PP)
ain2 = Pin('P1', Pin.OUT_PP)
bin1 = Pin('P2', Pin.OUT_PP)
bin2 = Pin('P3', Pin.OUT_PP)
ain1.low()
ain2.low()
bin1.low()
bin2.low()

pwma = Pin('P7')
pwmb = Pin('P8')
tim = Timer(4, freq=1000)
ch1 = tim.channel(1, Timer.PWM, pin=pwma)
ch2 = tim.channel(2, Timer.PWM, pin=pwmb)
ch1.pulse_width_percent(0)
ch2.pulse_width_percent(0)

def run(left_speed, right_speed):
if inverse_left==True:
left_speed=(-left_speed)
if inverse_right==True:
right_speed=(-right_speed)

if left_speed < 0:
    ain1.low()
    ain2.high()
else:
    ain1.high()
    ain2.low()
ch1.pulse_width_percent(abs(left_speed))

if right_speed < 0:
    bin1.low()
    bin2.high()
else:
    bin1.high()
    bin2.low()
ch2.pulse_width_percent(abs(right_speed))

这个要怎么解决啊

就像这样，一识别到小球就报这个错误